Solved 0 CH3 H2SO4 Treating 2methyl1butene with methanol
1 Bromo 1 Methylcyclohexane. The alkyl bromide is tertiary. The first set of conditions favors the e2 process, because sodium ethoxide is a strong base.two elimination products are.
Solved 0 CH3 H2SO4 Treating 2methyl1butene with methanol
The alkyl bromide is tertiary. Predict the products of this reaction,. The first set of conditions favors the e2 process, because sodium ethoxide is a strong base.two elimination products are. Web view the full answer transcribed image text: One ether and two alkenes. Thus, dehydrohalogenation of this compound gives only one alkene.
Predict the products of this reaction,. Thus, dehydrohalogenation of this compound gives only one alkene. Predict the products of this reaction,. The alkyl bromide is tertiary. One ether and two alkenes. The first set of conditions favors the e2 process, because sodium ethoxide is a strong base.two elimination products are. Web view the full answer transcribed image text:
